2x^2+57x-90=0

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Solution for 2x^2+57x-90=0 equation:



2x^2+57x-90=0
a = 2; b = 57; c = -90;
Δ = b2-4ac
Δ = 572-4·2·(-90)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-63}{2*2}=\frac{-120}{4} =-30 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+63}{2*2}=\frac{6}{4} =1+1/2 $

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